O(mn) time
count cells and shared edges
res = 4 * cells - 2 * shared edges
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
| class Solution { public: int islandPerimeter(vector<vector<int>>& grid) { int cnt = 0, shared = 0; for(int i = 0; i < grid.size(); ++i) { for(int j = 0; j < grid[i].size(); ++j) { if (grid[i][j]) { ++cnt; shared += (i > 0 && grid[i - 1][j]); shared += (j > 0 && grid[i][j - 1]); } } } return 4 * cnt - shared * 2; } };
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
| class Solution { public: int islandPerimeter(vector<vector<int>>& grid) { int perimeter = 0; for (int row = 0; row < grid.size(); ++row) { for (int col = 0; col < grid[row].size(); ++col) { if (grid[row][col]) { if (0 == row || 0 == grid[row - 1][col]) { ++perimeter; } if (grid.size() == row + 1 || 0 == grid[row + 1][col]) { ++perimeter; } if (0 == col || 0 == grid[row][col - 1]) { ++perimeter; } if (grid[row].size() == col + 1 || 0 == grid[row][col + 1]) { ++perimeter; } } } } return perimeter; } };
|