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480. Sliding Window Median

multiset/hashheap O(nlogk)
239. Sliding Window Maximum方法不一样,太smart了
讨论一下添加删除的四种情况即可,两个if都能cover

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class Solution {
public:
vector<double> medianSlidingWindow(vector<int>& nums, int k) {
int n = nums.size();
multiset<int> s(begin(nums), begin(nums) + k);
auto m = next(begin(s), k / 2);
vector<double> res;
for (int i = k; i <= n; ++i) {
res.push_back((k & 1) ? *m : (*prev(m) + double(*m)) * 0.5);
if (i == n) break;
s.insert(nums[i]);
if (nums[i] < *m) { // 偶变奇则需要前移
--m;
}
if (nums[i - k] <= *m) { // 如果要删除的数有可能是*m要提前对m作调整,否则删除以后m就spoil了
++m; // 奇变偶需要后移
}
s.erase(s.find(nums[i - k]));
}
return res;
}
};
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class Solution {
public:
vector<double> medianSlidingWindow(vector<int>& nums, int k) {
if (nums.empty()) return {};
int n = nums.size();
multiset<int> max, min;
for (int i = 0; i < k; ++i) {
max.insert(nums[i]);
}
for (int i = 0; i < k / 2; ++i) {
min.insert(*max.rbegin());
max.erase(max.find(*max.rbegin())); // Remember this usage!
}
vector<double> res;
for (int i = k; i < n; ++i) {
if (max.size() == min.size()) {
res.push_back(*max.rbegin() / 2.0 + *min.begin() / 2.0); // (a + b) / 2.0 could overflow!
}
else {
res.push_back(*max.rbegin());
}
if (max.count(nums[i - k])) {
max.erase(max.find(nums[i - k]));
max.insert(nums[i]);
}
else {
min.erase(min.find(nums[i - k]));
min.insert(nums[i]);
}
if (!max.empty() && !min.empty() && *max.rbegin() > *min.begin()) {
int tmp = *max.rbegin();
max.erase(max.find(tmp));
max.insert(*min.begin());
min.erase(min.begin());
min.insert(tmp);
}
}
if (max.size() == min.size()) {
res.push_back(*max.rbegin() / 2.0 + *min.begin() / 2.0);
}
else {
res.push_back(*max.rbegin());
}
return res;
}
};