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161. One Edit Distance

Posted on Edited on In Disqus:
Symbols count in article: 1.3k Reading time ≈ 1 mins.

O(m+n) time O(1) space

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class Solution {
public:
    bool isOneEditDistance(string s, string t) {
        int m = s.length(), n = t.length();
        if (m > n) {
            swap(s, t);
            swap(m, n);
        }
        if (n - m > 1) return false;
        for (int i = 0; i < m; ++i) {
            if (s[i] != t[i]) {
                if (m < n) return s.substr(i) == t.substr(i + 1);
                return s.substr(i + 1) == t.substr(i + 1);
            }
        }
        return m + 1 == n;
    }
};
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class Solution {
public:
    bool isOneEditDistance(string s, string t) {
        int m = s.length(), n = t.length();
        if (m > n) {
            return isOneEditDistance(t, s);
        }
        if (n - m > 1) return false;
        for (int i = 0; i < m; ++i) {
            if (s[i] != t[i]) {
                if (m < n) return s.substr(i) == t.substr(i + 1);
                return s.substr(i + 1) == t.substr(i + 1);
            }
        }
        return m + 1 == n;
    }
};
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class Solution {
public:
    bool isOneEditDistance(string s, string t) {
        int m = s.length(), n = t.length();
        if (m == n) {
            int diff = 1;
            for (int i = 0; i < n; ++i) {
                if (s[i] != t[i]) {
                    if (diff == 1) {
                        diff = 0;
                    } else {
                        return false;
                    }
                }
            }
            return diff == 0; // s和t都为空
        }
        if (m > n) {
            s.swap(t);
            swap(m, n);
        }
        if (n - m != 1) return false;
        int diff = 1;
        for (int i = 0, j = 0; i < m && j < n; ++i, ++j) {
            if (s[i] != t[j]) {
                if (diff == 1) {
                    --i;
                    diff = 0;
                } else {
                    return false;
                }
            }
        }
        return true;
    }
};