O(n) time O(1) space
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class Solution { public: Node* connect(Node* root) { Node dummy, *p = &dummy, *res = root; while (root) { if (root->left) { p->next = root->left; root->left->next = root->right; p = root->right; } root = root->next; if (!root) { root = dummy.next; dummy.next = nullptr; p = &dummy; } } return res; } };
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直接用117. Populating Next Right Pointers in Each Node II的方法也行
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class Solution { public: Node* connect(Node* root) { Node dummy, *p = &dummy, *res = root; while (root) { if (root->left) { p->next = root->left; p = p->next; } if (root->right) { p->next = root->right; p = p->next; } root = root->next; if (!root) { root = dummy.next; dummy.next = nullptr; p = &dummy; } } return res; } };
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O(n) time O(h) space
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class Solution { public: Node* connect(Node* root) { if (!root) return root; Node dummy_head, *tail = &dummy_head; for (auto p = root; p; p = p->next) { if (p->left) { tail->next = p->left; tail = tail->next; } if (tail->next) break; if (p->right) { tail->next = p->right; tail = tail->next; } if (tail->next) break; } connect(root->right); connect(root->left); return root; } };
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