0%

103. Binary Tree Zigzag Level Order Traversal

BFS O(n)

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
vector<vector<int>> res;
queue<TreeNode *> q{{root}};
while (!q.empty()) {
res.push_back({});
for (int i = q.size(); i > 0; --i) {
auto x = q.front(); q.pop();
if (x) {
res.back().push_back(x->val);
q.push(x->left);
q.push(x->right);
}
}
if (!(res.size() & 1)) {
reverse(begin(res.back()), end(res.back()));
}
}
res.pop_back();
return res;
}
};